The dungeon
Welcome to the dungeon! 😀
Cameo appearance in the first panel: Darrel, owned by GrumpyMonk.
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Put Rex as opponent for Amy : i’m sure she’ll lose her luck quickly ^_^”
Loose their focus, mess up their side of the challenge? Sounds like a plan, IF they notice her crush. Unless her luck lets her see Rex from a angle she likes, then that could have the same effect without them knowing about her crush… 😛
The malicious grin of luck
means she doesn’t give a… chance
for all the things you’ll try
the lady’ll make you dance.
You’re down in her domain
along with a tall, white, Fox?
You’re looking to play the game
where luck and chance interlocks.
Beating a truly stacked deck
is a task worthy of a knight.
But you need to be quick, young Kai;
as you haven’t got all night.
Cha!
Welcome to the Dungeon, we’ve got fun and games!
We got everything you want, bunny, we know the names
We are the people that can find whatever you may need
If you got no money, bunny honey, we got your disease
In the Dungeon, Welcome to the Dungeon won’t you bring me to your
Sha nanananananana knees knees! *Mwah* I wanna watch you bleed!
Welcome to the Dungeon, we take it day by day, if you want it you’re gonna bleed,
but it’s the price you pay
And you’re a very cutesy girl, you’re very hard to please, you can taste the lucky lights, but you won’t get there for free!
Just watch, I bet she’ll be beaten by her crush.
Critical distraction!
When I read this the first time, I read “eaten” instead of “beaten” xD
I mean, losing badly to someone could be said as “he’s eating him alive”, so I was thinking in that direction when I misread that xD
And beside that… Wolfs eat bunnies don’t they?
XD
Soooo….. three chances to win since there are 3 of them against her? What happens if they lose? No clue to the next location or perhaps a harder one?
Oh, no. They don’t get a clue until they win xD
They can keep trying :p
So they just keep going, until they beat the LUCKY BUNNY….?
…so how many DAYS did they have again? 😛
But… there are only three possible outcomes:
– 1 odd dice and 1 even dice = an odd number.
– 2 odd dice = an even number.
– 2 even dice = an even number.
Statistically if you always bet ‘even’ you’re likely to win overall!
Apparently, that’s not completely true. According to my research on the game, there’s an equal number of odd combinations as there are even combinations, making it a perfect 50% chance game.
Let’s just hope this group doesn’t get Zoro’d (if you know what I mean)
You mean like when Zoro(juro) was playing this against some cheating Yakuza in Wano?
Yep, there are 18 ways to get an odd sum and 18 ways to get an even sum, so the probabilities are equal. The use of two dice makes the game seem more complicated than it is. A single die or a coin toss would work just as well.
Found this.
https://en.wikipedia.org/wiki/Ch%C5%8D-han
Strictly, there are *four* possible, equally likely outcomes:
1st die odd, 2nd even = odd
1st even, 2nd odd = odd
2 odd = even
2 even = even
Your set of possibilities misses the fact that 1 odd 1 even is twice as likely as either of the others.
No, there a FOUR possible outcomes – you left out the first one
– 1 even dice and 1 odd dice = an odd number.
– 1 odd dice and 1 even dice = an odd number.
– 2 odd dice = an even number.
– 2 even dice = an even number.
If you build out an outcome table of the two dice being rolled, the answer becomes self-evident:
| 1 | 2 | 3 | 4 | 5 | 6
1| 2 | 3 | 4 | 5 | 6 | 7
2| 3 | 4 | 5 | 6 | 7 | 8
3| 4 | 5 | 6 | 7 | 8 | 9
4| 5 | 6 | 7 | 8 | 9 |10
5| 6 | 7 | 8 | 9 |10|11
6| 7 | 8 | 9 |10|11|12
Evens = 1 + 3 + 5 + 5 + 3 + 1 = 18
Odds = 2 + 4 + 6 + 4 + 2 = 18
Therefore, there’s a 50/50 chance for rolling either evens or odds.
If they wait until after she rolls, and make their decision than, that should help.
Need to find a way to make the decision that minimizes luck. Do like numbers game used to do. Look at yesterday’s stock market closing numbers.
I tried listing the permutations, it is 50/50.
f they wait until after she rolls, and make their decision than, that should help.
Won’t help. The dice stay concealed until all bets are in. It’s still luck. Especially is she ‘bets’ first.
Flip a “D2” (another name for a coin apparently) to decide?
try random[.]org – gives you a true random number.
My comment last week still stands: I love this comic!
I did some more research on the Ursa Major awards, and it sounds like your webcomic fits better in the Graphic Story category rather than the Comic Strip one. If anyone out there plans on writing in a nomination of their own, it would probably improve the odds if we all put it in the same category.
Little Amy is cute as hell in that last panel. Rex is in BIG TROUBLE.
Uh oh, I don’t like the look of that Bunny. Let’s hope Amy lucked out by meeting Rex and not making a fool of herself. Now she’s in her element, her luck and skill may have increased; however, Kai is also in his element now (Dungeons), so his power has increased as well. Plus, as a side comic demonstrated, Amy’s luck wasn’t enough to be safe from a happy Kaya pouncing on her, so perhaps Kaya (and Kai) are a stronger force than luck… Or at least Amy’s bunny luck. If so, Amy better hope she remembered to wear her four leaf clover underwear.
There’s a 50% chance a die could land on an even side and vice versa, so taking that into account for both dice Kai and friends have a 50/50 chance of getting it right. Unless Amy’s luck screws with the natural probability. Good thing the Twins are a part of the supernatural probability!
If I didn’t already know that Benji plays role-playing games, I would know it when he specifies six-sided dice. 🙂
The die have been cast, let’s see if their luck holds out against the dungeon’s lucky bunny.
The Die is already cast”. Alea iacta est. As said by Julius Caesar when he was told that crossing the Rubicon river would count as him invading Rome with his forces from Gaul. He simply pointed to the handful of his troops on the Rome side and stated that. One event, two sayings that have lasted for millennia. A very important moment in history.
If the Lucky Bunny is sneaky enough, she might be able to use the mechanics of the shell game to set the dice clandestinely, or even use loaded dice so that a particular number comes up more often. Which dice she uses depends on which the boys call.
I really like Amy’s look in the last panel; two is good also. 🙂
Come on, Rex.. You had -one- job! All you had to do is pat Amy on the head as you walked by. Her luck would be shorted out for the rest of the night. 🙂
Well, Rex did the next best thing…
…he shook her hand.
I’m sure that some of her “rabbits foot” luckhas rubbed off on him.
Actually, he’d have to touch her foot for that…
He has to touch her stinky feet for good luck? Hmmm, I wonder if it’s worth the smell…
Rex: “I am not touching those smelly things!
Amy: “(Internally) Rex said my feet stink… Does he hate me? Do my feet really smell that bad?” *Tears stream down her face.*
This is for the World Guide entry for this week: hybrids with antlers could have them sawn off, but reinstalled with pegs so that the antlers could be removed for changing clothes/sleeping/bathing, and replaced at need. The pegs could be made as breakaway, to avoid impact shocks being transmitted to the skull (among other things).
Assuming that antlers of hybrids works like the antlers of real deer, this would not work well, as deer lose their antlers and grow new ones every year.
Robin has already stated that hybrids with horns/antlers do not shed them on a yearly basis.
The World guide has not been updated this week yet.
If I wanted to beat her, I’d told her I’ve made a bet with Rex that if I win, he has to take her for a dinner or something.
I read about this game in an Usagi Yojimbo trade back in the ’00s.
This reminds me of the episode where this game is played in the anime series Samurai Champloo. It’s a game very much utilized by the Japanese Yakuza…
If they can find a blind massage expert in the next 15 minutes, they got this made…:)
Assuming that antlers of hybrids works like the antlers of real deer, this would not work well, as deer lose their antlers and grow new ones every year.
This was supposed to be a reply to Miscreant Mutt, but was accidently posted here, please delete if possible…
For those who want to discuss the odds, this is my impression:
2_&_12: one way each can appear
3_&_11: two ways each
4_&_10: 3 ways each
5_&_9: 4 ways each
6_&_8: 5 ways each
7: 6 ways
TOTALS:
Even: 2+6+10=18
Odd: 4+8+6=18
So, assuming that we don’t use “loaded” dice, my next question is, are these dice “casino” quality?
Casino dice are designed to maximize randomness.
The corners are mathematically sharp & precise, the bulk of the die is TRANSPARENT plastic, & the “pips” are filled in with a different plastic of the same density, otherwise (for example) the “6” would have significantly less material than the “1” on the opposite side. Unequally weighted sides would favor the higher (IE lighter) numbers showing slightly more often.
The reason I know this is I worked in a gaming store that sold casino dice. It turns out that casinos routinely “retire” their dice, & sell them to gaming stores, because they’re considered too worn out to be usable after one full day of play.
#TheMoreYouKnow
7 is the most likely sum, 2 and 12 the least likely.
…
I’ll guess odd, because I like odd numbers better.
Looks like the kids have gotten themselves into a…dice-y situation…
( •_•)>⌐■-■
(⌐■_■)
ヾ(⌐■_■)ノ♪ “YEAAAAAAAAAAAAAAAAHHHHHHHHH!!!”
I dunno. If I was put into a situation like this, I’d kinda feel cheated.
It’d be like having a basketball game between Michael Jordan and a toddler. Unless Michael is really gracious, it’s a guaranteed loss for the kiddo.
Sure, it’d be “an honor” to play with MJ, but saying that they have to win in order to advance feels like they have no chance.
I assume that they can keep playing until they win. In which case, I feel like the winning strategy is to pick an answer and stick with it. Once they’ve had the other answer happen ten times, the next question is to ask Amy how she’s controlling the dice.
Is Amy secretly a mythical hybrid as well?
Never bet against The lucky Bunny.
This is not making much sense as either a “game” or as a treasure hunt. I fail to see how this in any way satisfies the condition of solving puzzles (which implies using one’s intellect), from clues in order to advance in a quest.
First, absent psychic or physical cheating, either outcome is just a 50-50 guess. Chou-Han (even-odd), is nothing more than an elaborate coin flip – an equi-likely outcome guessing game. Even if one assumes Amy can manipulate the dice (or the players), it is still a 50-50 guess as to which way she choose.
Second – What is “winning”? A one-shot round? If not one-shot, best two out of three, three out of five, …?
Since this is a comic we are assured that they birthday group will succeed and progress to the next challenge (else it would terminate the current arc and preclude the forthcoming final race to the finish). However, I cannot resolve the two incompatible concepts.
This is the second part of this challenge, they had to figure out where to go.
Don’t know how I missed this before, but…
Panel 4: “face down” should be hyphenated.
Also, personal note: Six-sided dice, cups and the concept of odd & even numbers all existed outside of Japan, so it baffles me that such a relatively mundane game could’ve originated there, of all places. Seriously, the only thing about it that sounds Japanese is its name.
No.
It had to originate somewhere; why not Japan?
As you said; it’s a simple/mundame game. Likely it -was- also ‘thought-up’ in other places, but just died out again. Japan could be just the place that took it most to heart and kept it alive up to the present.
So a simple winning strategy is for them to stick to one decision until they get one?
I mean it is probable to get three odds or evens in a row, but still a better strategy than keep changing their minds at every call.
Both approaches would have the same odds of success.
You’d think so, but the odds of the same result happening over and over is exponential, the odds of one coin flip is 50%, of two flips being identical, 25%, 3 is 8%, etc. Guessing the same over and over would statistically result in a win faster than switching up
Nope. That’s called the Gambler’s Fallacy, where people incorrectly think that past results affect future odds. The thinking is that if you flip heads ten times in a row, it’s “due” for a tails on the next flip, but the reality is that it’s always 50-50. You could guess heads every time, tails every time, or alternate between guessing heads and tails, and your chances of hitting on each individual flip are always going to be 50-50.
That’s why they put those electronic signs on roulette tables that tell people what the last several spins have been. It tricks people into thinking they can see patterns (“it’s been red four times in a row, and five reds in a row is unlikely, so I’ll bet on black”) or use some kind of strategy to predict the next spin, but really every spin is random and not connected to previous spins.
More like game theory, the chance of landing on heads ten times in a row is statistically unlikely. In the case of a 50/50 game it’s usually smart to stick to one choice. A roulette table has way more permutations, hence why there’s no coin flipping game at casinos.
If you’re about to flip a coin ten times, then yes, it’s unlikely that it’s going to come up ten times in a row. But once you’ve flipped it nine times and gotten heads every time, what are the odds that the tenth will be heads also? 50-50, same as always. Since the game is just to guess the next single result, it doesn’t matter what the last results were or what your previous guesses were.
Or to put it another way – let’s say you’re going to flip a coin three times and try to guess each one, and you only have to get one correct to win. There are eight possible outcomes, all equally likely (HHH, HHT, HTH, HTT, THH, THT, TTH, TTT). If you decide to just guess heads for each one, then out of eight outcomes, you only lose on one of them (TTT), so you have a 7/8 chance of winning. If you guess all tails, you only lose on HHH, so it’s still a 7/8 chance to win.
Now you decide you don’t want to guess the same one every time, so you alternate and guess HTH. What are your odds now? You only lose on THT and win on all the others, so it’s still 7/8. You’re no better or worse off alternating your guesses as compared to guessing the same thing every time. Even if you had to guess all three correctly to win, you’d be just as likely to win guessing HHH as guessing HTH or THT (1/8 chance to win either way).
And yeah, with roulette they make money from the fact that the bets aren’t “fair” (for example, if you bet red or black, you have a slightly less than 50% chance of winning because of the 0 and 00). And as you say, they add more permutations and possible bets. This makes people think it’s possible to use strategy or some kind of “system” to predict the next spin, because as humans, we’re built to find patterns and we’re so good at it that we see patterns even when none are there. Casinos make a lot of money on this kind of thinking (from the guy at the craps table who thinks the dice are “hot” and starts betting big, or the lady who won’t leave a slot machine because it’s “due” for a jackpot).
Anyway, I’ll stop posting about this – sorry to Robin about the hijack, but I find the psychology behind this kind of thing interesting. Even if we don’t agree, I appreciate the discussion!
Do you by any chance watch a yt channel cled the primer? He does a lot of stuff like this, using computer simulations for visual effect. Even did a coin flipping probability video. Something tells me you’ll enjoy it. Won’t post the link because the comment won’t post if I do, but it might be worth checking out
Never heard of him, but I’ll check it out.
But overall my point is, the results of the dice are random and chaotic, if you change your guess randomly you’re adding another layer of chaotic randomness to the situation, keeping to one guess narrows it down. Sure odds don’t actually mean something will or won’t happen, it’s just a very educated guess, but when trying to win a game you want to minimize as many variables as possible